MATH SOLVE

5 months ago

Q:
# PLEASE HELP I NEED THIS WITHIN THE HOUR OR I'LL FAIL!1. Samara is adjusting a satellite because she finds it is not focusing the incoming radio waves perfectly. The shape of her satellite can be modeled by y^2=2(x+6), where x and y are modeled in inches. She realizes that the static is a result of the feed antenna shifting slightly off the focus point. What is the focus point of the satellite?A. (–5.5, 0)B. (0, –5.5)C. (0.5, 0)D. (5.5, 0) 2. Which is the standard form of the equation of the parabola that has a vertex of (–4, –6) and a directrix of y = 3?3. Franco is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satellite can be modeled by y^2+6y-3x+3=0, where x and y are modeled in inches. He realizes that the static is a result of the feed antenna shifting slightly off the focus point. What is the focus point of the satellite?A. (2, –3)B. (–1.25, –3)C. (3, 2.75)D. (3, 4.75)4. What is the standard form of the equation of a parabola with a focus of (0, –3) and its vertex at the origin?

Accepted Solution

A:

1:This is a parabola by the looks of the equation and the fact that it's a
satellite dish. The vertex of the equation is (-6,0) and the focus is
2/4, 1/2. 1/2 plus -6 is -5.5. the focus is (-5.5,0).

This answer is only true if the actual equation is y^2 not 2y

2:y=-(x+3)^2/8+1

3:This is the answer(–1.25, –3),

4:

answer is: x^2=-12y

This answer is only true if the actual equation is y^2 not 2y

2:y=-(x+3)^2/8+1

3:This is the answer(–1.25, –3),

4:

answer is: x^2=-12y