Solve the following system of equations by the substitution method.8x = 2y + 53x = y + 7What is the solution set?{(-41/2, -9/2)}{(-9/2, -41/2)}∅

Answer:Solution set: {(-9/2, -41/2)}Step-by-step explanation:Given that:8x = 2y + 5  -------- eq13x = y + 7 ---------- eq2From eq2 we get:y =3x -7 ------ eq3Now putting this value of y in eq1 we get:8x = 2(3x - 7) + 5By simplifying we get:8x = 6x - 14 + 58x = 6x -98x - 6x = -92x = -9x = -9/2Putting value of x in eq3y =3(-9/2) -7y = -27/2 -7Taking LCMy = -27/2 - 14/2y = -41/2Hence,Solution set: {(-9/2, -41/2)}Now substituting the values of x and y in eq1 and eq2:8(-9/2) = 2(-41/2) + 5-72/2 = -41 + 5-36 = -36Hence proved3x = y + 7 3(-9/2) = (-41/2) + 7-27/2 = -27/2Hence provedi hope it will help you!